Using standard order of precedence for arithmetic operations, 30+50*5 = 30+ 250 = 280.

Answer: 280

If helmet + helmet - helmet = 30, then 30 + 30 - 30 = 30, so helmet = 30

If quiver + quiver + helmet = 130, then 50 + 50 + 30 = 130, so quiver = 50

If quiver - double axe - helmet = 10, then 50 - 10 - 30 = 10, so double axe = 10

Therefore helmet + quiver x single axe = ?

If double axe = 10, then single axe = 5

30 + 50 x 5 = 30 + 250 = 280  ;-)

280

280; basic arithmetic, assuming a double axe is equal to 2*axe...

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Part 1: Plus and minus cancel each other.  Helmet=30

Part 2: 130 minus a helmet .=100.  Two quivers=100, therefore one quiver=50

Part 3: 50 minus double axe minus 30 =10, so double axe = 50 minus 30 minus 10 = 10

400

Macht alles zusammen : 7500

3900