jssamp2003 said:
How are the defense points of a defense force with mixed types applied to an attacking force consisting also of mixed types of units?
I will use an example with Balur's units because BG is fresh in my mind.
Say 117 Marennon, 42 orcs, 2 orcish raiders, 123 ogres get attacked by an offense of 8 wyverns, 10 warlocks, 11 knights, and 15 paladins.
Do the orcs have 20 defense or 60 because paladins are present? Are the ogres 60 to the knights but 180 with respect to the warlocks? Is the percentage of each type of attacking unit used as a weighting factor for the total defense points? Rarely do you see attacks made with only one type of unit.
And how is it that in a successful defense of a village where all of the evil units are killed but only less than 50% of each type of defending units get killed, that the single legendary unit with them is killed? If a 100% of the single unit is killed then 100% of the others should die as well. Or do legendary units not follow the same system of defense points / total defense plus offense points?
Defense points are based on weighted percentage - If 50% of your attack force's strength is Bestiary then 50% of Marennon will have 240 defense and the other 50% will have 80 defense.
This is true of all defense units, not just balur defense
Single Units will not die if you send 2.5x BG Strength. ( but a safety margin is recommended)
Perhaps your Legendary should have survived, but we would need very complicated arithmetic to check this. It is possible that your exact loss percentage was 50.5% so the legendary died but you only lost half your army.
If you definitely lost less than half we certainly have a problem - algorithm nerf?
!00 single units at level 20 have over 75k offense and can kill 30k balur defense with no loss
Tournament points are calculated as one-fiftieth of battleground ranking - Battleground Ranking is 10% of average BG Strength - http://prntscr.com/crc3rf
... and if anyone needs to know, Power Points are one-fortieth of base unit strength - so Dragon = 1680/40 = 42 pp