280.

If:

A = 1 Helmet

B = 1  Quiver

C = 1 Axe

Then:

A+A-A=30; A=30; 1 Helmet = 30

B+B+A=130; 2B+30=130; 2B=130-30; 2B=100; B=100/2; B=50; 1 Quiver = 50

B-2C-A=10; 50-2C-30=10; 2C=10; C=5; 1 Axe = 5

A+BxC=?; 30+50x5=?; 30+250=280

If helmet + helmet - helmet = 30, then 30 + 30 - 30 = 30, so helmet = 30

If quiver + quiver + helmet = 130, then 50 + 50 + 30 = 130, so quiver = 50

If quiver - double axe - helmet = 10, then 50 - 10 - 30 = 10, so double axe = 10

If helmet + quiver x single axe = ? and if 1/2axe=5 then 30+(50X5)= 280

Therefore my answer is 280

Helmet=30 Quiver=50 Double Axe=10 Single Axe=5 30 + 50 = 80 x 5 = 400

280

The answer is 280.

Helmet = 30

Quiver = 50

Double Axe = 10

Single Axe = 5


Useful link regarding the order in which you need to do the last question:

https://en.wikipedia.org/wiki/Order_of_operations

1. 30+30-30=30

2. 50+50+30=130

3. 50-10-30=10

4. each axe=5

5. 30+50x5 --->30+250=280
my answer is 280, 400 is wrong answer....guys u dnt know simple maths who has answered 400....
always multiplication is the priority than addition...go back to your 1st or 2nd standrad and take session on maths lol.

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and solution is 400

Hi all,

helmet is 30

quiver is 50

double axes is 10

Therefore single axe must be 5