1200

H+H-H = 30, then 2H-H = 30, so H= 30

Q+ Q+ helmet = 130, then 2Q+H = 130, so Q= 50

Q -  2A - H = 10, then 50 - 10 - 30 = 10, 2A = 10

Therefore H+Q * A = ?

30+50*5=280

280

Remember that you must follow the rules of addition and multiplication so you must mutiple before you add

If helmet + helmet - helmet = 30, then 30 + 30 - 30 = 30, so helmet = 30

If quiver + quiver + helmet = 130, then 50 + 50 + 30 = 130, so quiver = 50

If quiver - double axe - helmet = 10, then 50 - 10 - 30 = 10, so double axe = 10

Therefore helmet + quiver x single axe = ?

If double axe = 10, then single axe = 5

30 + (50 * 5) =x

30 + (250) = x

280 = x

400