If helmet + helmet - helmet = 30, then 30 + 30 - 30 = 30, so helmet = 30

If quiver + quiver + helmet = 130, then 50 + 50 + 30 = 130, so quiver = 50

If quiver - double axe - helmet = 10, then 50 - 10 - 30 = 10, so double axe = 10

Therefore helmet + quiver x single axe = ? 

If double axe = 10, then single axe = 5

30 + 50 x 5 = 400, so ? = 400

let A be the helmet

     B be the quiver

     C be the axe; 

then

     A+A-A=30 ; A=30

     B+B+A=130 ; 2B+30=130 ; B=(130-30)/2 ; B=50

     B-2C-A=10 ; 2C=B-A ; C=(50-30-10)/2 ; C=5

hence,

     helmet + quiver x axe =  A+BxC

                                        = 30+50x5

                                        =280

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Leave a a post with the solution below if wisdom and fortune are on your side!

30 + 30 - 30 = 30

50 + 50 +30 = 130

50- 10 - 30 = 10

30 + 50 x 10 = 530

Hi all,

helmet is 30

quiver is 50

double axes is 10

and solution is 400