Х10 again... How to increase the chance by 10 times and at the same time reduce it by 80 times
Sorry for my English, I am from Russia.
I translated this text online.
Dear players, let's try to consider the increased chance of a call, namely X10, from the point of view of mathematics. Increase the chance of getting a hero by ten times! Amazing!? As if not so, everything is exactly the opposite. I will immediately make a reservation that I will take as an example X10 for a certain leg, regardless of its element, we will start from their total number. Start.
The game has a total of 80 leg. heroes.
The chance of falling out of the legendary hero is specified immediately - it is 6% = 0.06%
Under X10, we are given the opportunity to summon a specific hero, which, as I said, is 80. Accordingly, one hero out of 80 or 1/80 = 0.0125 percent.
This is followed by multiplying the probabilities to find the total probability.
0.06% multiplied by 0.0125% = 0.00075%
For not the most adult player, no offense, just for specifics, maybe you are still in elementary school and these numbers do not mean anything to you, this call only means that only 75 people out of 10,000 will get the same Lega.
Why, you may ask, will the chance decrease by 80 times, because with X10 it is written that the chances of summoning a legendary hero remain unchanged? This is true. But people don't count percentages, they see X10 and that's enough for them. And since the initial chance is 0.06%, we divide it this way: 0.06/0.00075 and we get 80. the Chance eventually decreased by 80 times.
Plarium management understands this and stamps these X10, instead of x2, and this should not be. Thank you all for your attention.